(6x+3)^2-(6x-5)*(6x+5)+2=0

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Solution for (6x+3)^2-(6x-5)*(6x+5)+2=0 equation: 



(6x+3)^2-(6x-5)(6x+5)+2=0

We use the square of the difference formula

36x^2+(6x+3)^2+25+2=0

We add all the numbers together, and all the variables

36x^2+(6x+3)^2+27=0

We move all terms containing x to the left, all other terms to the right

36x^2+(6x+3)^2=-27

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